The equilibrium constant: how far reactions go

Learn what the equilibrium constant K means, how to write its expression, what large and small K values tell you, and why pure solids and liquids are left out.

Quick answer

The equilibrium constant K is the ratio of product concentrations to reactant concentrations at equilibrium, each raised to its stoichiometric coefficient. It measures how far a reaction proceeds.

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}

Unit: unitless

Example: For N₂O₄(g) ⇌ 2NO₂(g) at 25 °C, Kc = 4.66 × 10⁻³. With [N₂O₄] = 0.050 M and [NO₂] = 0.015 M at equilibrium, Kc = (0.015)²/0.050 = 0.0045, matching the known value.

What you will learn

  • Write the Kc expression for any balanced equation.
  • Interpret large versus small K values in terms of reaction extent.
  • Explain why pure solids and pure liquids are omitted from K expressions.
  • Convert between K values for reversed or scaled equations.

The law of mass action

At equilibrium, the ratio of product concentrations to reactant concentrations settles at a fixed value — the equilibrium constant. For the general reaction

aA+bB⇌cC+dDaA + bB \rightleftharpoons cC + dD

the concentration equilibrium constant is

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}

This is the law of mass action: each concentration is raised to its stoichiometric coefficient. K is a property of the reaction at a given temperature — the same reaction at the same temperature always has the same K, regardless of starting amounts.

Reading K: large, small, and in-between

The magnitude of K is a direct readout of how far the reaction goes:

  • K >> 1 (say, 10¹⁰): the reaction goes essentially to completion; products dominate at equilibrium.
  • K << 1 (say, 10⁻¹⁰): the reaction barely proceeds; reactants dominate.
  • K ≈ 1: significant amounts of both sides coexist at equilibrium.

For N₂O₄ ⇌ 2NO₂ at 25 °C, Kc = 4.66 × 10⁻³ — much less than 1, so an equilibrium mixture is mostly colorless N₂O₄ with a little brown NO₂. Warming the mixture darkens it as the equilibrium shifts — a visible K in action.

Why solids and liquids vanish from K

Pure solids and pure liquids never appear in K expressions. Their concentrations — amount per unit volume of the pure substance — are constant (density divided by molar mass does not change as the solid reacts), so they are folded into K itself.

For CaCO₃(s) ⇌ CaO(s) + CO₂(g), the expression is simply Kc = [CO₂]. Adding more solid limestone does not shift anything: only the gas concentration matters. The same logic applies to the solvent in dilute solutions — water is omitted from aqueous K expressions.

K and equation bookkeeping

K belongs to the equation as written. Manipulate the equation and K follows strict rules:

  • Reverse the equation: K' = 1/K
  • Multiply coefficients by n: K' = Kⁿ
  • Add two equations: K' = K₁ × K₂

Related constants include Kp for gases (built from partial pressures instead of concentrations), connected by Kp = Kc(RT)^Δn where Δn is the change in moles of gas. And K always refers to one temperature — change T, and K changes (which direction depends on whether the reaction is exo- or endothermic).

Variables and units

SymbolNameUnitMeaning
[C],[D][C], [D]Product concentrationMEquilibrium concentration of a product species
a,b,c,da, b, c, dCoefficientunitlessStoichiometric coefficient in the balanced equation

Common mistakes

✗ K tells you how fast equilibrium is reached.

K is pure thermodynamics: it describes the ratio of products to reactants at equilibrium. Speed is kinetics' business (rate constants). A huge K with a huge activation barrier means a reaction that 'wants' to happen but takes forever.

✗ The exponents in the K expression are the reaction orders.

For the equilibrium expression, exponents are the stoichiometric coefficients from the balanced equation — always. Reaction orders are measured and belong to rate laws. The two look alike but come from completely different reasoning.

✗ Pure solids and liquids are left out because their concentrations are zero.

They are left out because their concentrations are effectively constant — a pure solid's 'concentration' (density/molar mass) does not change as it reacts. Constants get absorbed into K itself.

Real-world applications

  • Haber process: K values at different temperatures tell engineers the best compromise between yield and rate.

  • Solubility prediction: Ksp (a special K) predicts whether a precipitate forms.

  • Biochemistry: binding constants (a form of K) quantify how tightly drugs grip their targets.

  • Geochemistry: mineral stability in groundwater is computed from equilibrium constants.

Frequently asked questions

Does K have units?

Formally K is built from activities (effective concentrations relative to a standard state), which are unitless — so K itself is unitless. In practice, chemists often write concentrations in the expression, but the thermodynamic K carries no units.

What happens to K if I double the balanced equation?

Square the entire expression: for the doubled equation, K' = K². In general, multiplying an equation by n raises K to the nth power, and reversing the equation inverts K (K' = 1/K).

Does K depend on the starting concentrations?

No — K describes the ratio at equilibrium, not the route there. Different starting mixtures that reach the same equilibrium state give the same K. If your computed K varies with starting conditions, the system was not at equilibrium.

Can two sources list different K values for the 'same' reaction?

Only if the equation is written differently. K is tied to the balanced equation as written: 2HI ⇌ H₂ + I₂ has K' = 1/54.3 for the reverse of H₂ + I₂ ⇌ 2HI (K = 54.3). Always check which direction the equation faces.