Gas pressure and its units

What gas pressure is, how barometers measure it, and how to convert between atm, mmHg, torr, Pa, kPa, bar, and psi.

Quick answer

Gas pressure is the force of countless particle collisions spread over the walls of a container, measured as force per unit area. Atmospheric pressure at sea level is defined as 1 atm.

1 atm=760 mmHg=760 torr=101.325 kPa=14.7 psi1\ \text{atm} = 760\ \text{mmHg} = 760\ \text{torr} = 101.325\ \text{kPa} = 14.7\ \text{psi}

Example: A weather report of 30.0 inches of mercury equals about 762 mmHg, just above the standard 760 mmHg of 1 atm, signaling fair-weather high pressure.

What you will learn

  • Define gas pressure as force per unit area at the particle level.
  • Explain how a mercury barometer measures atmospheric pressure.
  • Convert fluently between atm, mmHg, torr, Pa, kPa, bar, and psi.
  • Choose the right pressure unit and the matching R value for gas-law problems.

Pressure as force per area

Gas pressure is force divided by area: the total push of particle collisions spread over the surface they strike. Double the collisions per second and the pressure doubles; spread the same collisions over twice the wall area and the pressure halves.

The SI unit is the pascal (Pa), one newton per square meter. A pascal is tiny: atmospheric pressure is over a hundred thousand of them. That is why scientists usually work in kilopascals (kPa) and define the standard atmosphere as

1 atm=101,325 Pa=101.325 kPa1\ \text{atm} = 101{,}325\ \text{Pa} = 101.325\ \text{kPa}

A useful sense of scale: 1 atm presses about 10 newtons onto every square centimeter, roughly the weight of a liter of water balanced on a postage stamp. You are not crushed because air and fluid inside your body push back with equal pressure.

A worked example: a textbook problem gives a tire pressure of 35.0 psi. Convert to atmospheres using 14.7 psi=1 atm14.7\ \text{psi} = 1\ \text{atm}: 35.0÷14.7≈2.3835.0 \div 14.7 \approx 2.38 atm. That reading is gauge pressure, measured above the atmosphere, so the absolute pressure inside is about 3.38 atm, a reminder to check whether a problem wants gauge or absolute values.

The barometer and mercury units

In 1643 Torricelli filled a glass tube with mercury, inverted it into a dish, and watched the column fall to about 760 mm. Air pressure pushing on the dish's surface supported the column, and its height became the first quantitative measure of the atmosphere.

That experiment is the origin of millimeters of mercury (mmHg) and the torr, named for Torricelli. By definition:

1 atm=760 mmHg=760 torr1\ \text{atm} = 760\ \text{mmHg} = 760\ \text{torr}

Mercury was chosen because it is dense: water would need a column over 10 meters tall to balance the atmosphere. Modern barometers use electronic sensors, but weather maps in the United States still report inches of mercury, and blood pressure cuffs still read in mmHg.

A worked example: a storm report lists 29.2 inches of mercury. Convert: 29.2×25.4=741.729.2 \times 25.4 = 741.7 mmHg, then 741.7÷760≈0.976741.7 \div 760 \approx 0.976 atm. Falling pressure below 1 atm signals an approaching storm, which is why sailors watched the barometer.

Converting between pressure units

Chemistry problems mix units freely, so one conversion chain handles them all:

1 atm=760 mmHg=760 torr=101.325 kPa=1.01325 bar=14.7 psi1\ \text{atm} = 760\ \text{mmHg} = 760\ \text{torr} = 101.325\ \text{kPa} = 1.01325\ \text{bar} = 14.7\ \text{psi}

The strategy is always the same: multiply by a fraction equal to one, arranged so the unwanted unit cancels. Write the starting unit, then chain conversion factors until only the target unit survives.

A worked example with two hops: convert 2.50 atm to psi. First hop to kPa: 2.50×101.325=253.32.50 \times 101.325 = 253.3 kPa. The psi equivalent of 1 atm is 14.7, so skip kPa entirely and go direct: 2.50×14.7=36.82.50 \times 14.7 = 36.8 psi. Now reverse it to check: 36.8÷14.7≈2.5036.8 \div 14.7 \approx 2.50 atm. Round-trip checks catch upside-down conversion factors, the most common unit error in gas-law work.

Memorize the atm row and derive the rest. Every other conversion is just the atm chain with one end swapped.

Matching units to the gas constant

The unit you choose dictates the gas constant you must use in PV=nRTPV = nRT. The two pairings to memorize:

  • Pressure in atm with volume in liters goes with R=0.08206 L⋅atm/(mol⋅K)R = 0.08206\ \text{L·atm/(mol·K)}.
  • Pressure in kPa with volume in liters goes with R=8.314 L⋅kPa/(mol⋅K)R = 8.314\ \text{L·kPa/(mol·K)}, and pressure in Pa with volume in cubic meters goes with R=8.314 J/(mol⋅K)R = 8.314\ \text{J/(mol·K)}.

Mixing an atm pressure with the 8.314 constant is the single most common ideal-gas-law error, and it silently shifts answers by a factor of about 100.

A worked example: 0.500 mol of gas at 2.00 atm and 300 K occupies V=nRT/P=(0.500×0.08206×300)÷2.00=6.15V = nRT/P = (0.500 \times 0.08206 \times 300) \div 2.00 = 6.15 L. Redo it in kilopascals: 2.00 atm=202.652.00\ \text{atm} = 202.65 kPa, so V=(0.500×8.314×300)÷202.65=6.15V = (0.500 \times 8.314 \times 300) \div 202.65 = 6.15 L. Same answer, as it must be; the unit system is a choice, not a property of the gas.

Common mistakes

✗ Pressure and force are the same thing.

Pressure is force spread over an area. The same force on a smaller area gives higher pressure, which is why a sharp nail pierces but a flat board does not.

✗ A vacuum has negative pressure.

Pressure bottoms out at zero, a perfect vacuum. Gauges that read 'negative' are really reporting pressure below the surrounding atmosphere, not below zero.

✗ mmHg measures a length, so it can't be a pressure.

It is shorthand: the height of a mercury column that the pressure can support. A pressure of 760 mmHg holds up exactly 760 millimeters of mercury, so the length encodes the pressure.

Real-world applications

  • Reading tire gauges, weather reports, and scuba tank dials

  • Calibrating laboratory manometers and barometers

  • Converting between engineering and scientific pressure specs

  • Interpreting blood pressure readings in mmHg

Frequently asked questions

Why does chemistry still use mmHg instead of just pascals?

It is historical. Torricelli's mercury barometer read atmospheric pressure directly as a column height in millimeters, and the unit stuck. Modern SI uses the pascal, but medicine and meteorology kept the old units.

Are torr and mmHg exactly the same?

Because 1 atm is defined as exactly 760 torr, they are interchangeable for any calculation. The torr is simply the more modern name for the same pressure unit.

Is the pascal really force divided by area?

Yes, and it is the SI unit: one pascal is one newton per square meter. It is inconveniently small for everyday pressures, so kilopascals are the practical choice; standard atmosphere is 101.325 kPa.

If air pressure is so strong, why don't we feel crushed?

Air pressure is real and strong: at sea level it presses with about 10 newtons on every square centimeter. You do not feel it because the same pressure pushes from inside your body outward, balancing the load.