Dilution: lowering concentration with M1V1 = M2V2

Dilution lowers concentration by adding solvent. Learn the M1V1 = M2V2 equation, how to prepare dilutions from stock, and the acid-to-water safety rule.

Quick answer

Dilution is the process of lowering a solution's concentration by adding more solvent. Because no solute is added or removed, the moles of solute stay constant, which gives the dilution equation M1V1 = M2V2 relating the stock and final concentrations and volumes.

M1V1=M2V2M_1V_1 = M_2V_2

Unit: M in mol/L; V in any consistent volume unit (both sides the same)

Example: To make 500 mL of 0.100 M NaCl from 1.00 M stock: V1 = (0.100 × 500) / 1.00 = 50.0 mL of stock, then add water to a total of 500 mL.

What you will learn

  • Explain dilution as conservation of solute moles during solvent addition
  • Apply M1V1 = M2V2 to find any one of the four quantities
  • Calculate the stock volume needed to prepare a target dilute solution
  • Plan serial dilutions for very large dilution factors
  • State and justify the 'add acid to water' safety rule

What dilution is

Dilution is the simplest operation in solution chemistry: take a concentrated stock solution, add solvent, and get a larger volume of a weaker solution. Labs work this way because one carefully prepared stock bottle can supply months of working solutions at many different concentrations.

The governing principle is conservation of solute. Adding pure solvent changes neither the identity nor the amount of the dissolved substance — it only spreads the same moles through more liquid. Everything about dilution math flows from that single fact.

Deriving M1V1 = M2V2

Write the moles before and after dilution. Before: n1=M1V1n_1 = M_1 V_1. After: n2=M2V2n_2 = M_2 V_2. Since no solute is added or removed, n1=n2n_1 = n_2, and therefore:

M1V1=M2V2M_1V_1 = M_2V_2

By convention, subscript 1 marks the concentrated stock and subscript 2 marks the dilute target. The volumes must be in the same unit on both sides — both in mL, or both in L — but they do not need to be liters, because the units cancel in the ratio.

Worked example: 500 mL of 0.100 M from 1.00 M stock

Problem: prepare 500 mL of 0.100 M NaCl from a 1.00 M stock solution.

  1. Identify the knowns: M1=1.00M_1 = 1.00 M, M2=0.100M_2 = 0.100 M, V2=500V_2 = 500 mL.
  2. Solve for the stock volume: V1=M2V2/M1V_1 = M_2V_2 / M_1.
  3. Substitute: V1=(0.100×500)/1.00=50.0V_1 = (0.100 \times 500) / 1.00 = 50.0 mL.
  4. Measure 50.0 mL of the 1.00 M stock with a graduated cylinder.
  5. Transfer to a 500 mL volumetric flask and add water to the mark.

The check: 1.00×50.0=50.01.00 \times 50.0 = 50.0 millimoles before, 0.100×500=50.00.100 \times 500 = 50.0 millimoles after. The water added is 500−50.0=450500 - 50.0 = 450 mL, not 500 mL — a distinction the equation does not spell out but the procedure requires.

Serial dilutions

When the dilution factor is enormous — say a million-fold — no single step is practical, so chemists chain dilutions in series. Each step multiplies the dilution factors: three successive 1:100 dilutions give (1/100)3=1/1,000,000(1/100)^3 = 1/1{,}000{,}000.

Serial dilution is standard in microbiology and analytical chemistry because each transfer uses comfortable, accurately measurable volumes. The trade-off is error accumulation: a 1% pipetting error repeated over five steps compounds, so critical serial dilutions use calibrated micropipettes and the final concentration is verified instrumentally.

Safety: add acid to water

Diluting concentrated acids deserves its own safety rule: always add acid to water, never water to acid. Mixing concentrated sulfuric or hydrochloric acid with water releases substantial heat of dilution. Water poured onto dense concentrated acid can sit on top, boil violently from the heat below, and spatter corrosive liquid.

The safe procedure: put most of the water in the receiving vessel first, then pour the acid in slowly down the wall of the vessel while stirring, allowing heat to dissipate into the large water volume. Wear splash goggles and gloves, work with modest volumes, and let the mixture cool before bringing it to its final volume.

Avoiding the classic errors

Two habits prevent nearly every dilution error. First, label which side is the stock: M1 and V1 always belong to the more concentrated starting solution. Swapping the subscripts inverts the answer. Second, remember that V2 is the final total volume, so the solvent added is V2 − V1.

Unit vigilance matters as well. If M is in mol/L and V2 is in mL, V1 comes out in mL — consistent units on both sides are enough, and converting to liters is unnecessary as long as both volumes match. A final reasonableness check always helps: the stock volume must be smaller than the final volume, since you are diluting.

Variables and units

SymbolNameUnitMeaning
M1M_1stock molaritymol/LConcentration of the stock solution
V1V_1stock volumemL or LVolume of stock solution to measure out
M2M_2final molaritymol/LTarget concentration after dilution
V2V_2final volumemL or LFinal total volume of the diluted solution

Common mistakes

✗ Dilution changes the number of moles of solute.

Dilution only adds solvent, so the moles of solute stay exactly the same. What changes is the volume they occupy, which lowers the concentration. M1V1 = M2V2 is true precisely because n1 = n2.

✗ You can pour water into concentrated acid as long as you stir.

Never add water to concentrated acid. The heat of dilution can flash-boil water trapped under the denser acid, spattering corrosive liquid. Always add the acid to a larger volume of water, slowly, with stirring.

✗ M1V1 = M2V2 also tells you how much water to add.

The equation gives V1, the volume of stock to measure out. The water added is the difference: V2 − V1. For the worked example below, you measure 50.0 mL of stock and then bring the total to 500 mL — you do not add 500 mL of water.

✗ Diluting a solution twice by half is the same as diluting once to a quarter.

That statement is actually correct, not a myth — it is included here because students often doubt it. Two successive 1:2 dilutions multiply the dilution factors: (1/2) × (1/2) = 1/4. Serial dilutions multiply, which is why microbiology uses them for huge dilution factors.

Real-world applications

  • Preparing working solutions from concentrated laboratory stock bottles

  • Serial dilutions in biology and medicine, e.g., antibiotic susceptibility testing

  • Titration: diluting a primary standard to the exact working concentration

  • Home and pool chemistry: diluting concentrated chlorine or acid safely

  • Pharmaceutical compounding: bringing a concentrated drug solution to dose strength

  • Environmental labs: diluting samples into an instrument's calibration range

Frequently asked questions

Why does M1V1 = M2V2 work?

Because the moles of solute do not change — only solvent is added, and no solute is created or destroyed. Moles before dilution equal moles after dilution, and since moles = M × V, it follows that M1V1 = M2V2. The equation is a bookkeeping statement, not a new chemical law.

Does the dilution equation work for units other than molarity?

Yes. Any concentration unit that is proportional to amount per volume works: molality with kilograms of solvent, mass percent with grams, even ppm. The derivation only needs the amount of solute to be conserved and the unit to scale linearly with that amount. Just keep the same unit on both sides.

Can I reverse a dilution if I added too much water?

You cannot un-dilute by adding solute-free solvent — dilution is one-way. To re-concentrate you must either evaporate solvent or add more solute, and computing the new concentration then requires knowing how much was added or removed. Keep concentrated stocks sealed and labeled so you rarely need to go backward.

What does 'add acid to water' mean in practice?

It means add the concentrated acid to the water, slowly, with stirring — never pour water into concentrated acid. Adding water to concentrated acid can cause violent localized boiling and spattering of corrosive liquid. The mnemonic taught in every lab is: do what you oughta, add acid to water.

How do I make a very dilute solution from a very concentrated stock?

Use the dilution equation with V1 as the unknown: V1 = M2V2 / M1 = (0.0200 M × 0.250 L) / 6.00 M = 0.000833 L = 0.833 mL. Measuring 0.833 mL accurately is impractical with ordinary glassware, so a better plan is a two-step serial dilution: first make an intermediate stock (e.g., 0.200 M), then dilute from that.